(1/31/99) (1/31/99)

Physics 623
Johnson Noise
Jan 31, 1999

Answer the questions 1 through 15 in this writeup before coming to the lab. They will be collected at the beginning of the lab. Read the sections of the text referenced here, if you haven't already.


1  Purpose

2   Introduction

The Johnson noise voltage ``spectral density'' that appears across a resistor is en = [Ö(4kBTR)]. (See sections 7.11-7.14; pp 430-443 in Horowitz-Hill 2nd edition.) For a 1M resistor at room temperature (300 K) en = 1.3 ×10-7  V/[ÖHz], or ~ mV rms in a 1 KHz bandwidth. We will, therefore, need a high gain amplifier whose intrinsic noise is small so that it does not cover up the thermal noise from the resistor.

3  Procedure

For the first amplifier stage, start near the left edge of the upper breadboard block (to the left of your tuned amplifier) and wire the following circuit:

noisefig1.gif
Figure 1:

Clip the component leads short and bend them so the component bodies lie flat against the breadboard - this minimizes stray capacitances. Use a single bus on the socket for all the grounds (probably the inner strip below the op-amp). It is a good idea to put 0.1 mF capacitors from the +15 V and the -15 V supply pins of each op-amp to ground to bypass the power supply.

The LF357 is an inexpensive op-amp with JFET input transistors and reasonably low noise. Use information from the spec sheet to find the following.

[Question 1] What is the gain of this stage (measured from the + input)?
[Question 2] The voltage noise spectral density (en) at the input due to the op-amp voltage noise? Use values for f ~ 1 kHz.
[Question 3] The voltage noise spectral density at the input due to the op-amp current noise (in) (for the circuit with Rin = 1M)?
[Question 4] The total voltage noise at the input from these two amplifier-related sources (remember that independent random voltages add in quadrature!)?
[Question 5] The noise temperature of this op-amp with Rin = 1M?
[Question 6] The noise figure for the op-amp with Rin = 1M? (See Section 7.12 in Horowitz-Hill, 2nd edition.)
[Question 7] The noise resistance of the op-amp?
[Questions 8] Repeat 2) through 7) for an OP-27 ultra-low noise bipolar input op-amp:
en = 3 nV/[ÖHz], in = 0.4 pA/[ÖHz].

[Question 9] Which is the better op-amp for this application?

Since we will use the DVM to measure an rms voltage, vrms, we need to define a bandwidth so that this voltage can be predicted from the Johnson noise spectral density, en.

Now refer to your previous laboratory (Operational Amplifiers) and consider the three stage tuned amplifier that you previously constructed on the right side of the top block of the breadboard.

[Question 10] What is f°, the center of the bandpass? (As usual, remember the difference between f(Hz) and w(rad/sec))

The use of the three stages results in a better definition of the bandwidth and reduces the gain at 60 Hz ( << f°) to the point where we have some hope of operating a completely unshielded high gain circuit like this in the presence of the large line-frequency fields in the laboratory. The overall gain is sketched below:

noisefig22.gif
Figure 2:

[Question 11] What is the gain of the three stage amplifier at f=60 Hz?
[Question 12] How many db down from the peak gain is this?

[Power levels, such as 30 watt or 40 watt, are often compared by taking the logarithm of the ratio of the Power levels. When comparing two power levels Pa and Pb, we might generate
n = log10([(Pa)/( Pb)])
and say the ``Power difference is n bels''.  More usually, we generate
m = 10.0 log10([(Pa)/( Pb)])
and we say the ``Power difference is m decibels'' or ``a is m db above b''. When comparing voltages, across identical resistors R, then the ratio of the powers in the resistors is related to the ratio of the voltages.
m = 10.0 log10([(Pa)/( Pb)]) = 10.0 log10([(V2a/R)/( V2b/R)])    = 20.0 log10([(Va)/( Vb)])

For example, if the voltage Va at a is twice the voltage Vb at b, then
m = 20.0 log10(2/1) = 20.0×(0.3010) = 6.02
and we say that ``the voltage at a is 6 decibels or 6 db above the voltage at b''. Note that this applies only if the two systems have the same impedance to ground. Perhaps both signals are moving in 50 ohm transmission lines.

One can compare voltage gains in the same way as comparing voltages. For example, if a voltage gain is increased two-fold, then it has been raised by 6 db.]

Confirm that the three tuned stages are connected together, but for the moment don't connect the output of the LM357 stage to the input of the first tuned stage.

Now we need to calculate the rms output voltage we expect for a given voltage spectral density at the input. We will assume ``white noise'', where the spectral density, en is independent of frequency. The rms input voltage in a bandwidth df at any frequency f is then en [Ödf], and the output voltage is A(f)en[Ödf] . We must add these voltages for all frequencies where we have any gain, but since the phases are random and independent, we must add their squares:

vrms2 = áv2 ñ = ¥
ó
õ
° 
( [ gain(f) ] en)2 df
= ¥
ó
õ
° 
en2 [ gain(f) ]2 df = ¥
ó
õ
° 
en2 [ 1st stage gain]2 é
ê
ë
(30)3 (f/f°)3
(1 + (f/f° )2)3
ù
ú
û
2

 
df

[Question 13] Show that:
vrms = en é
ê
ë
(1st stage gain)(303) æ
è
  æ
Ö

f°
 
ö
ø
æ
ç
è
¥
ó
õ
° 
é
ê
ë
x
1+x2
ù
ú
û
6

 
dx ö
÷
ø
1/2

 
ù
ú
û

[Question 14] Given that
¥
ó
õ
° 
æ
ç
è
x
1+x2
ö
÷
ø
6

 
dx = 3p
512
find the numerical value for k such that vrms-out = ken.

The peak gain of the tuned stages is quite sensitive to the exact values of the capacitors. If you want accurate results, it would be a good idea to remeasure the net gain of the three tuned stages at the frequency where it is maximum, and scale your calculated k to the extent that the measure value differs from 303/8. To do this, we use a sine wave from the signal generator as a source, inserting the ¸100 and ¸10 attenuators in order to set to a sufficiently low voltage. It is best to use your scope to measure the input and output voltages.

[Question 15] By what factor did you expect it to drop?

Note: save your breadboard in the cabinet again - you will use it for the Phase Detector Lab next week.

THE PHASE DETECTOR
(See Section 15.15, pp 1031-4 in Horowitz-Hill)
Answer questions 1 and 2 in this writeup before coming to the lab. Read the referenced sectiuons if you have not already done this.

You will use your 3-stage tuned amplifier and low-noise input stage from the Johnson Noise lab. Construct the following circuit on the lower breadboard block as far to the right as possible (to keep it away from the 357 input). Be sure the square wave input comes in from the right side of the breadboard. (You should not be using either of the BNC connectors on the left.)

(You can use any one of the six devices on the 7404 chip. Note that it requires connections to ground and to Vcc = 5 V. Note also that the HI-300 requires a ground connection for input reference control. )

noisefig3.gif
Figure 3:

Set the pulse generator to give a 0-4V square wave output at a frequency near f°. Replace the resistor at the amplifier input with a 1 K and add a photodiode as shown below:

noisefig42.gif
Figure 4:

Put a ~ 25 mm piece of black tubing over the end or your photodiode to limit the amount of background light that strikes it. Bend the leads so it is aimed nearly horizontally of the left end of your breadboard, trying to point it a a part of the room that is not too bright (set up a dark screen, if necessary). Put a red LED in series with a 100 ohm resistor at the end of a coax cable and connect it also to the pulse output.

noisefig52.gif
Figure 5:

[Question 2] What rms fluctuation do you expect in the output of this filter due to the Johnson noise in the 1M resistor?
(Forget your integral over the tuned amplifier gain now - your gain(f) is almost a delta function at f°. The width is 2× the bandwidth of the low-pass filter: BW = [(p)/2][1/(2pRC)]. The effective bandwidth is smaller than this by 1/2, since noise components 90° out of phase with the reference don't give any output - even though they are at the correct frequency.)


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On 31 Jan 1999, 17:32.